Recently I am trying to calculate the BSE and IQP transition dipole based on VASP lecture on BSE and BSE fatband. However, I have a few questions regarding the BSE and IQP oscillator strength. From the slides, it says that the BSE oscillator strength is:
$$ \tag{1} | ( f_{ck} - f_{vk} ) F_{cvk} A_{cvk} |^2 $$
where the IQP oscillator strength is:
$$\tag{2} F_{cvk} = \dfrac{\langle \psi_c | p_i | \psi_v \rangle}{E_{ck} - E_{vk}}$$
My question is about the parameters in the two formula and how they connect to each other:
In the BSE formula, is $( f_{ck} - f_{vk} )$ set to be 1? Or it depends on smearing?
Does $i$ in the formula for $F_{cvk}$ mean Cartesian coordinate? If so, do I need to add $x$, $y$, and $z$ contributions to get a total $F_{cvk}$?
Are $ \langle \psi_c | p_i | \psi_v \rangle$ and
CDER_BETWEEN_STATES(NB1,NB2,NK,ISP,1:3)
the same parameter? If so, what is the unit of $ \langle \psi_c | p_i | \psi_v \rangle$?Since the
WAVEDER
contains spin up and spin down, do we need to add them up to get a total $F_{cvk}$?For $A_{cvk}$, I notice that in
BSEFATBAND
, column 6 is the absolute value of coupling coefficient (radius of circles), and column 9/10 is the real/imaginary part of the coupling coefficient. I notice that we need to multiple $Nk^3$ to column 9/10 to make the absolute value equal to column 6. I do not know which $A_{cvk}$ should I use to get the BSE oscillator strength.As we can get $F_{cvk}$ from
WAVEDER
, $A_{cvk}$ fromBSEFATBAND
, can we use these parameters to get the BSE oscillator strength output invasprun.xml
? I have tried to do this but I could not establish a correspondence between the BSE oscillator strength formula and thevasprun.xml
output.
Any insights for any questions would be super helpful to my research. Thank you for your kind help!
Best regards,
Bo