5
$\begingroup$

I am looking into double perovskite materials. One of the possible materials is Cs4CuSb2Cl12. Now, although there are a few papers which have done ab intio calculations but none of the common open databases have cif file for this structure(COD and materials project). The paper which I am currently looking into has submitted there data to ICSD, but I do not have access.

Due to which I have decided to start working on my own cif file. An older answer gave a brief description on how to do this using VESTA(and I am also comfortable with the software) , but I still have some doubts. Mainly how does one calculate the spatial coordinates of each atoms and how do we add the term U(which I suppose is the energy of some sort).

If anyone has any idea how I can obtain the cif file or how to go about finding the coordinates and finally making a cif file(please also mention what other information do I need apart from the space group and lattice parameters)

$\endgroup$
3
  • $\begingroup$ Why not try contacting the authors? Also it seems the paper has given a good amount of information regarding the bond lengths in the free supplementary information section. Also, there is another software called Avogadro which as I remember can be used to draw the unit cell which can later be optimized using DFT. $\endgroup$
    – PBH
    Sep 26 at 15:55
  • 1
    $\begingroup$ @PBH I have actually contacted the author and hopefully they will be sending me the cif file. But I actually wanted to learn too, thanks for mentioning Avogadro, I will take a look. But the question still remains how to get the coordinates of each respective atom. I have started to study crystallography(in more depth) and stuff like wikcoff positions but not really sure if I am headed in the correct direction $\endgroup$ Sep 27 at 7:12
  • $\begingroup$ ICSD structures can also be obtained from the Cambridge Crystallographic Data Centre (CCDC). The structure in the paper you mentioned is available from here $\endgroup$ Oct 5 at 3:52

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.