In classical MD simulations of lattice structures, whenever we are trying to incorporate vdW corrections to the atomic force calculation, we need to set up cutoff length beyond which the vdW correction is not considered to keep the computational cost manageable. As a result, the classical simulation requires reasonably large supercell(usually with its dimensions twice as long as the cutoff length) to capture vdW interactions.

When it comes to DFT calculations, however, the cutoff lengths for nonlocal vdW corrections, such as the rVV10 functional, are not explicitly set in DFT softwares like Quantum ESPRESSO. And it is common practice to use primitive cells in DFT calculations along with nonlocal vdW functionals. By looking at the formalism of rVV10 vdW correction, the integration of the functional is clearly performed within a volume, $$ E_{c}^{n l}=\frac{\hbar}{2} \iint n(\mathbf{r}) \Phi\left(n, n^{\prime},|\nabla n|,\left|\nabla n^{\prime}\right|,\left|\mathbf{r}-\mathbf{r}^{\prime}\right|\right) n\left(\mathbf{r}^{\prime}\right) d \mathbf{r} d \mathbf{r}^{\prime}\tag{1} $$ where $n(\mathbf{r})$ is the charge density at location of $\mathbf{r}$. So my question is what are the lower and upper limits for the equation (1)? and how do we decide them?

To attack this question, I try to understand Eqn.(1) in terms of its Fourier transform, $$ E_{c}^{n l}=\frac{\hbar}{2} \Omega \sum_{i j} \sum_{\mathbf{G}} \tilde{\theta}_{i}^{*}(\mathbf{G}) \tilde{\Phi}^{\mathrm{rVV} 10}\left(q_{i}, q_{j},|\mathbf{G}|\right) \tilde{\theta}_{j}(\mathbf{G})\tag{2} $$ where $\tilde{\Phi}^{\mathrm{rVV} 10}\left(q_{i}, q_{j},|\mathbf{G}|\right)$ are the Fourier transforms of the rVV10 kernel evaluated on a bidimensional grid of $q$ values, and $\tilde{\theta}_{i}$ are the Fourier transforms of $\theta_{i}$ introduced in the rVV10 paper here. But now my question is: how does the wavevector in the reciprocal space $\mathbf{G}$ is related to the cutoff length of vdW correction? I have a feeling that I might be pursuing the answer in a wrong line of thinking, so any hint will be appreciated!

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  • $\begingroup$ +10. Nice first question! I see you've been here for 8 months but I'm meeting you for the first time now, so welcome to our new community and thank you very much for contributing your question here! We hope to see much more of you in the future, and thanks also for formatting yoru question so nicely, including equation number labels!!! Here's a related question which might interest you: mattermodeling.stackexchange.com/q/63/5 $\endgroup$ Nov 24 at 21:50

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